3.289 \(\int \frac {\cot ^3(c+d x) (A+B \tan (c+d x))}{(a+b \tan (c+d x))^3} \, dx\)

Optimal. Leaf size=352 \[ \frac {(2 A b-a B) \cot (c+d x)}{a^2 d (a+b \tan (c+d x))^2}-\frac {\left (a^2 A+3 a b B-6 A b^2\right ) \log (\sin (c+d x))}{a^5 d}+\frac {b \left (-2 a^3 B+5 a^2 A b-3 a b^2 B+6 A b^3\right )}{2 a^3 d \left (a^2+b^2\right ) (a+b \tan (c+d x))^2}+\frac {x \left (a^3 (-B)+3 a^2 A b+3 a b^2 B-A b^3\right )}{\left (a^2+b^2\right )^3}+\frac {b \left (a^5 (-B)+3 a^4 A b-6 a^3 b^2 B+11 a^2 A b^3-3 a b^4 B+6 A b^5\right )}{a^4 d \left (a^2+b^2\right )^2 (a+b \tan (c+d x))}-\frac {b^3 \left (-10 a^5 B+15 a^4 A b-9 a^3 b^2 B+17 a^2 A b^3-3 a b^4 B+6 A b^5\right ) \log (a \cos (c+d x)+b \sin (c+d x))}{a^5 d \left (a^2+b^2\right )^3}-\frac {A \cot ^2(c+d x)}{2 a d (a+b \tan (c+d x))^2} \]

[Out]

(3*A*a^2*b-A*b^3-B*a^3+3*B*a*b^2)*x/(a^2+b^2)^3-(A*a^2-6*A*b^2+3*B*a*b)*ln(sin(d*x+c))/a^5/d-b^3*(15*A*a^4*b+1
7*A*a^2*b^3+6*A*b^5-10*B*a^5-9*B*a^3*b^2-3*B*a*b^4)*ln(a*cos(d*x+c)+b*sin(d*x+c))/a^5/(a^2+b^2)^3/d+1/2*b*(5*A
*a^2*b+6*A*b^3-2*B*a^3-3*B*a*b^2)/a^3/(a^2+b^2)/d/(a+b*tan(d*x+c))^2+(2*A*b-B*a)*cot(d*x+c)/a^2/d/(a+b*tan(d*x
+c))^2-1/2*A*cot(d*x+c)^2/a/d/(a+b*tan(d*x+c))^2+b*(3*A*a^4*b+11*A*a^2*b^3+6*A*b^5-B*a^5-6*B*a^3*b^2-3*B*a*b^4
)/a^4/(a^2+b^2)^2/d/(a+b*tan(d*x+c))

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Rubi [A]  time = 1.25, antiderivative size = 352, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.161, Rules used = {3609, 3649, 3651, 3530, 3475} \[ \frac {b \left (11 a^2 A b^3+3 a^4 A b-6 a^3 b^2 B+a^5 (-B)-3 a b^4 B+6 A b^5\right )}{a^4 d \left (a^2+b^2\right )^2 (a+b \tan (c+d x))}+\frac {b \left (5 a^2 A b-2 a^3 B-3 a b^2 B+6 A b^3\right )}{2 a^3 d \left (a^2+b^2\right ) (a+b \tan (c+d x))^2}-\frac {\left (a^2 A+3 a b B-6 A b^2\right ) \log (\sin (c+d x))}{a^5 d}-\frac {b^3 \left (17 a^2 A b^3+15 a^4 A b-9 a^3 b^2 B-10 a^5 B-3 a b^4 B+6 A b^5\right ) \log (a \cos (c+d x)+b \sin (c+d x))}{a^5 d \left (a^2+b^2\right )^3}+\frac {x \left (3 a^2 A b+a^3 (-B)+3 a b^2 B-A b^3\right )}{\left (a^2+b^2\right )^3}+\frac {(2 A b-a B) \cot (c+d x)}{a^2 d (a+b \tan (c+d x))^2}-\frac {A \cot ^2(c+d x)}{2 a d (a+b \tan (c+d x))^2} \]

Antiderivative was successfully verified.

[In]

Int[(Cot[c + d*x]^3*(A + B*Tan[c + d*x]))/(a + b*Tan[c + d*x])^3,x]

[Out]

((3*a^2*A*b - A*b^3 - a^3*B + 3*a*b^2*B)*x)/(a^2 + b^2)^3 - ((a^2*A - 6*A*b^2 + 3*a*b*B)*Log[Sin[c + d*x]])/(a
^5*d) - (b^3*(15*a^4*A*b + 17*a^2*A*b^3 + 6*A*b^5 - 10*a^5*B - 9*a^3*b^2*B - 3*a*b^4*B)*Log[a*Cos[c + d*x] + b
*Sin[c + d*x]])/(a^5*(a^2 + b^2)^3*d) + (b*(5*a^2*A*b + 6*A*b^3 - 2*a^3*B - 3*a*b^2*B))/(2*a^3*(a^2 + b^2)*d*(
a + b*Tan[c + d*x])^2) + ((2*A*b - a*B)*Cot[c + d*x])/(a^2*d*(a + b*Tan[c + d*x])^2) - (A*Cot[c + d*x]^2)/(2*a
*d*(a + b*Tan[c + d*x])^2) + (b*(3*a^4*A*b + 11*a^2*A*b^3 + 6*A*b^5 - a^5*B - 6*a^3*b^2*B - 3*a*b^4*B))/(a^4*(
a^2 + b^2)^2*d*(a + b*Tan[c + d*x]))

Rule 3475

Int[tan[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[Log[RemoveContent[Cos[c + d*x], x]]/d, x] /; FreeQ[{c, d}, x]

Rule 3530

Int[((c_) + (d_.)*tan[(e_.) + (f_.)*(x_)])/((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(c*Log[Re
moveContent[a*Cos[e + f*x] + b*Sin[e + f*x], x]])/(b*f), x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d,
0] && NeQ[a^2 + b^2, 0] && EqQ[a*c + b*d, 0]

Rule 3609

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*tan[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*tan[(e
_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*(A*b - a*B)*(a + b*Tan[e + f*x])^(m + 1)*(c + d*Tan[e + f*x])^(n
+ 1))/(f*(m + 1)*(b*c - a*d)*(a^2 + b^2)), x] + Dist[1/((m + 1)*(b*c - a*d)*(a^2 + b^2)), Int[(a + b*Tan[e +
f*x])^(m + 1)*(c + d*Tan[e + f*x])^n*Simp[b*B*(b*c*(m + 1) + a*d*(n + 1)) + A*(a*(b*c - a*d)*(m + 1) - b^2*d*(
m + n + 2)) - (A*b - a*B)*(b*c - a*d)*(m + 1)*Tan[e + f*x] - b*d*(A*b - a*B)*(m + n + 2)*Tan[e + f*x]^2, x], x
], x] /; FreeQ[{a, b, c, d, e, f, A, B, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0]
&& LtQ[m, -1] && (IntegerQ[m] || IntegersQ[2*m, 2*n]) &&  !(ILtQ[n, -1] && ( !IntegerQ[m] || (EqQ[c, 0] && NeQ
[a, 0])))

Rule 3649

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*t
an[(e_.) + (f_.)*(x_)] + (C_.)*tan[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[((A*b^2 - a*(b*B - a*C))*(a + b*T
an[e + f*x])^(m + 1)*(c + d*Tan[e + f*x])^(n + 1))/(f*(m + 1)*(b*c - a*d)*(a^2 + b^2)), x] + Dist[1/((m + 1)*(
b*c - a*d)*(a^2 + b^2)), Int[(a + b*Tan[e + f*x])^(m + 1)*(c + d*Tan[e + f*x])^n*Simp[A*(a*(b*c - a*d)*(m + 1)
- b^2*d*(m + n + 2)) + (b*B - a*C)*(b*c*(m + 1) + a*d*(n + 1)) - (m + 1)*(b*c - a*d)*(A*b - a*B - b*C)*Tan[e
+ f*x] - d*(A*b^2 - a*(b*B - a*C))*(m + n + 2)*Tan[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C,
n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0] && LtQ[m, -1] &&  !(ILtQ[n, -1] && ( !I
ntegerQ[m] || (EqQ[c, 0] && NeQ[a, 0])))

Rule 3651

Int[((A_.) + (B_.)*tan[(e_.) + (f_.)*(x_)] + (C_.)*tan[(e_.) + (f_.)*(x_)]^2)/(((a_) + (b_.)*tan[(e_.) + (f_.)
*(x_)])*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])), x_Symbol] :> Simp[((a*(A*c - c*C + B*d) + b*(B*c - A*d + C*d
))*x)/((a^2 + b^2)*(c^2 + d^2)), x] + (Dist[(A*b^2 - a*b*B + a^2*C)/((b*c - a*d)*(a^2 + b^2)), Int[(b - a*Tan[
e + f*x])/(a + b*Tan[e + f*x]), x], x] - Dist[(c^2*C - B*c*d + A*d^2)/((b*c - a*d)*(c^2 + d^2)), Int[(d - c*Ta
n[e + f*x])/(c + d*Tan[e + f*x]), x], x]) /; FreeQ[{a, b, c, d, e, f, A, B, C}, x] && NeQ[b*c - a*d, 0] && NeQ
[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0]

Rubi steps

\begin {align*} \int \frac {\cot ^3(c+d x) (A+B \tan (c+d x))}{(a+b \tan (c+d x))^3} \, dx &=-\frac {A \cot ^2(c+d x)}{2 a d (a+b \tan (c+d x))^2}-\frac {\int \frac {\cot ^2(c+d x) \left (2 (2 A b-a B)+2 a A \tan (c+d x)+4 A b \tan ^2(c+d x)\right )}{(a+b \tan (c+d x))^3} \, dx}{2 a}\\ &=\frac {(2 A b-a B) \cot (c+d x)}{a^2 d (a+b \tan (c+d x))^2}-\frac {A \cot ^2(c+d x)}{2 a d (a+b \tan (c+d x))^2}+\frac {\int \frac {\cot (c+d x) \left (-2 \left (a^2 A-6 A b^2+3 a b B\right )-2 a^2 B \tan (c+d x)+6 b (2 A b-a B) \tan ^2(c+d x)\right )}{(a+b \tan (c+d x))^3} \, dx}{2 a^2}\\ &=\frac {b \left (5 a^2 A b+6 A b^3-2 a^3 B-3 a b^2 B\right )}{2 a^3 \left (a^2+b^2\right ) d (a+b \tan (c+d x))^2}+\frac {(2 A b-a B) \cot (c+d x)}{a^2 d (a+b \tan (c+d x))^2}-\frac {A \cot ^2(c+d x)}{2 a d (a+b \tan (c+d x))^2}+\frac {\int \frac {\cot (c+d x) \left (-4 \left (a^2+b^2\right ) \left (a^2 A-6 A b^2+3 a b B\right )+4 a^3 (A b-a B) \tan (c+d x)+4 b \left (5 a^2 A b+6 A b^3-2 a^3 B-3 a b^2 B\right ) \tan ^2(c+d x)\right )}{(a+b \tan (c+d x))^2} \, dx}{4 a^3 \left (a^2+b^2\right )}\\ &=\frac {b \left (5 a^2 A b+6 A b^3-2 a^3 B-3 a b^2 B\right )}{2 a^3 \left (a^2+b^2\right ) d (a+b \tan (c+d x))^2}+\frac {(2 A b-a B) \cot (c+d x)}{a^2 d (a+b \tan (c+d x))^2}-\frac {A \cot ^2(c+d x)}{2 a d (a+b \tan (c+d x))^2}+\frac {b \left (3 a^4 A b+11 a^2 A b^3+6 A b^5-a^5 B-6 a^3 b^2 B-3 a b^4 B\right )}{a^4 \left (a^2+b^2\right )^2 d (a+b \tan (c+d x))}+\frac {\int \frac {\cot (c+d x) \left (-4 \left (a^2+b^2\right )^2 \left (a^2 A-6 A b^2+3 a b B\right )+4 a^4 \left (2 a A b-a^2 B+b^2 B\right ) \tan (c+d x)+4 b \left (3 a^4 A b+11 a^2 A b^3+6 A b^5-a^5 B-6 a^3 b^2 B-3 a b^4 B\right ) \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx}{4 a^4 \left (a^2+b^2\right )^2}\\ &=\frac {\left (3 a^2 A b-A b^3-a^3 B+3 a b^2 B\right ) x}{\left (a^2+b^2\right )^3}+\frac {b \left (5 a^2 A b+6 A b^3-2 a^3 B-3 a b^2 B\right )}{2 a^3 \left (a^2+b^2\right ) d (a+b \tan (c+d x))^2}+\frac {(2 A b-a B) \cot (c+d x)}{a^2 d (a+b \tan (c+d x))^2}-\frac {A \cot ^2(c+d x)}{2 a d (a+b \tan (c+d x))^2}+\frac {b \left (3 a^4 A b+11 a^2 A b^3+6 A b^5-a^5 B-6 a^3 b^2 B-3 a b^4 B\right )}{a^4 \left (a^2+b^2\right )^2 d (a+b \tan (c+d x))}-\frac {\left (a^2 A-6 A b^2+3 a b B\right ) \int \cot (c+d x) \, dx}{a^5}-\frac {\left (b^3 \left (15 a^4 A b+17 a^2 A b^3+6 A b^5-10 a^5 B-9 a^3 b^2 B-3 a b^4 B\right )\right ) \int \frac {b-a \tan (c+d x)}{a+b \tan (c+d x)} \, dx}{a^5 \left (a^2+b^2\right )^3}\\ &=\frac {\left (3 a^2 A b-A b^3-a^3 B+3 a b^2 B\right ) x}{\left (a^2+b^2\right )^3}-\frac {\left (a^2 A-6 A b^2+3 a b B\right ) \log (\sin (c+d x))}{a^5 d}-\frac {b^3 \left (15 a^4 A b+17 a^2 A b^3+6 A b^5-10 a^5 B-9 a^3 b^2 B-3 a b^4 B\right ) \log (a \cos (c+d x)+b \sin (c+d x))}{a^5 \left (a^2+b^2\right )^3 d}+\frac {b \left (5 a^2 A b+6 A b^3-2 a^3 B-3 a b^2 B\right )}{2 a^3 \left (a^2+b^2\right ) d (a+b \tan (c+d x))^2}+\frac {(2 A b-a B) \cot (c+d x)}{a^2 d (a+b \tan (c+d x))^2}-\frac {A \cot ^2(c+d x)}{2 a d (a+b \tan (c+d x))^2}+\frac {b \left (3 a^4 A b+11 a^2 A b^3+6 A b^5-a^5 B-6 a^3 b^2 B-3 a b^4 B\right )}{a^4 \left (a^2+b^2\right )^2 d (a+b \tan (c+d x))}\\ \end {align*}

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Mathematica [C]  time = 6.50, size = 320, normalized size = 0.91 \[ \frac {(3 A b-a B) \cot (c+d x)}{a^4 d}-\frac {A \cot ^2(c+d x)}{2 a^3 d}-\frac {\left (a^2 A+3 a b B-6 A b^2\right ) \log (\tan (c+d x))}{a^5 d}+\frac {b^3 (A b-a B)}{2 a^3 d \left (a^2+b^2\right ) (a+b \tan (c+d x))^2}+\frac {b^3 \left (-4 a^3 B+5 a^2 A b-2 a b^2 B+3 A b^3\right )}{a^4 d \left (a^2+b^2\right )^2 (a+b \tan (c+d x))}-\frac {b^3 \left (-10 a^5 B+15 a^4 A b-9 a^3 b^2 B+17 a^2 A b^3-3 a b^4 B+6 A b^5\right ) \log (a+b \tan (c+d x))}{a^5 d \left (a^2+b^2\right )^3}+\frac {(A+i B) \log (-\tan (c+d x)+i)}{2 d (a+i b)^3}+\frac {(A-i B) \log (\tan (c+d x)+i)}{2 d (a-i b)^3} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(Cot[c + d*x]^3*(A + B*Tan[c + d*x]))/(a + b*Tan[c + d*x])^3,x]

[Out]

((3*A*b - a*B)*Cot[c + d*x])/(a^4*d) - (A*Cot[c + d*x]^2)/(2*a^3*d) + ((A + I*B)*Log[I - Tan[c + d*x]])/(2*(a
+ I*b)^3*d) - ((a^2*A - 6*A*b^2 + 3*a*b*B)*Log[Tan[c + d*x]])/(a^5*d) + ((A - I*B)*Log[I + Tan[c + d*x]])/(2*(
a - I*b)^3*d) - (b^3*(15*a^4*A*b + 17*a^2*A*b^3 + 6*A*b^5 - 10*a^5*B - 9*a^3*b^2*B - 3*a*b^4*B)*Log[a + b*Tan[
c + d*x]])/(a^5*(a^2 + b^2)^3*d) + (b^3*(A*b - a*B))/(2*a^3*(a^2 + b^2)*d*(a + b*Tan[c + d*x])^2) + (b^3*(5*a^
2*A*b + 3*A*b^3 - 4*a^3*B - 2*a*b^2*B))/(a^4*(a^2 + b^2)^2*d*(a + b*Tan[c + d*x]))

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fricas [B]  time = 1.15, size = 1065, normalized size = 3.03 \[ -\frac {A a^{10} + 3 \, A a^{8} b^{2} + 3 \, A a^{6} b^{4} + A a^{4} b^{6} + {\left (A a^{8} b^{2} + 3 \, A a^{6} b^{4} - 9 \, B a^{5} b^{5} + 14 \, A a^{4} b^{6} - 3 \, B a^{3} b^{7} + 6 \, A a^{2} b^{8} + 2 \, {\left (B a^{8} b^{2} - 3 \, A a^{7} b^{3} - 3 \, B a^{6} b^{4} + A a^{5} b^{5}\right )} d x\right )} \tan \left (d x + c\right )^{4} + 2 \, {\left (A a^{9} b + B a^{8} b^{2} - 2 \, B a^{6} b^{4} + 6 \, B a^{4} b^{6} - 11 \, A a^{3} b^{7} + 3 \, B a^{2} b^{8} - 6 \, A a b^{9} + 2 \, {\left (B a^{9} b - 3 \, A a^{8} b^{2} - 3 \, B a^{7} b^{3} + A a^{6} b^{4}\right )} d x\right )} \tan \left (d x + c\right )^{3} + {\left (A a^{10} + 4 \, B a^{9} b - 8 \, A a^{8} b^{2} + 12 \, B a^{7} b^{3} - 30 \, A a^{6} b^{4} + 23 \, B a^{5} b^{5} - 45 \, A a^{4} b^{6} + 9 \, B a^{3} b^{7} - 18 \, A a^{2} b^{8} + 2 \, {\left (B a^{10} - 3 \, A a^{9} b - 3 \, B a^{8} b^{2} + A a^{7} b^{3}\right )} d x\right )} \tan \left (d x + c\right )^{2} + {\left ({\left (A a^{8} b^{2} + 3 \, B a^{7} b^{3} - 3 \, A a^{6} b^{4} + 9 \, B a^{5} b^{5} - 15 \, A a^{4} b^{6} + 9 \, B a^{3} b^{7} - 17 \, A a^{2} b^{8} + 3 \, B a b^{9} - 6 \, A b^{10}\right )} \tan \left (d x + c\right )^{4} + 2 \, {\left (A a^{9} b + 3 \, B a^{8} b^{2} - 3 \, A a^{7} b^{3} + 9 \, B a^{6} b^{4} - 15 \, A a^{5} b^{5} + 9 \, B a^{4} b^{6} - 17 \, A a^{3} b^{7} + 3 \, B a^{2} b^{8} - 6 \, A a b^{9}\right )} \tan \left (d x + c\right )^{3} + {\left (A a^{10} + 3 \, B a^{9} b - 3 \, A a^{8} b^{2} + 9 \, B a^{7} b^{3} - 15 \, A a^{6} b^{4} + 9 \, B a^{5} b^{5} - 17 \, A a^{4} b^{6} + 3 \, B a^{3} b^{7} - 6 \, A a^{2} b^{8}\right )} \tan \left (d x + c\right )^{2}\right )} \log \left (\frac {\tan \left (d x + c\right )^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) - {\left ({\left (10 \, B a^{5} b^{5} - 15 \, A a^{4} b^{6} + 9 \, B a^{3} b^{7} - 17 \, A a^{2} b^{8} + 3 \, B a b^{9} - 6 \, A b^{10}\right )} \tan \left (d x + c\right )^{4} + 2 \, {\left (10 \, B a^{6} b^{4} - 15 \, A a^{5} b^{5} + 9 \, B a^{4} b^{6} - 17 \, A a^{3} b^{7} + 3 \, B a^{2} b^{8} - 6 \, A a b^{9}\right )} \tan \left (d x + c\right )^{3} + {\left (10 \, B a^{7} b^{3} - 15 \, A a^{6} b^{4} + 9 \, B a^{5} b^{5} - 17 \, A a^{4} b^{6} + 3 \, B a^{3} b^{7} - 6 \, A a^{2} b^{8}\right )} \tan \left (d x + c\right )^{2}\right )} \log \left (\frac {b^{2} \tan \left (d x + c\right )^{2} + 2 \, a b \tan \left (d x + c\right ) + a^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) + 2 \, {\left (B a^{10} - 2 \, A a^{9} b + 3 \, B a^{8} b^{2} - 6 \, A a^{7} b^{3} + 3 \, B a^{6} b^{4} - 6 \, A a^{5} b^{5} + B a^{4} b^{6} - 2 \, A a^{3} b^{7}\right )} \tan \left (d x + c\right )}{2 \, {\left ({\left (a^{11} b^{2} + 3 \, a^{9} b^{4} + 3 \, a^{7} b^{6} + a^{5} b^{8}\right )} d \tan \left (d x + c\right )^{4} + 2 \, {\left (a^{12} b + 3 \, a^{10} b^{3} + 3 \, a^{8} b^{5} + a^{6} b^{7}\right )} d \tan \left (d x + c\right )^{3} + {\left (a^{13} + 3 \, a^{11} b^{2} + 3 \, a^{9} b^{4} + a^{7} b^{6}\right )} d \tan \left (d x + c\right )^{2}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(d*x+c)^3*(A+B*tan(d*x+c))/(a+b*tan(d*x+c))^3,x, algorithm="fricas")

[Out]

-1/2*(A*a^10 + 3*A*a^8*b^2 + 3*A*a^6*b^4 + A*a^4*b^6 + (A*a^8*b^2 + 3*A*a^6*b^4 - 9*B*a^5*b^5 + 14*A*a^4*b^6 -
3*B*a^3*b^7 + 6*A*a^2*b^8 + 2*(B*a^8*b^2 - 3*A*a^7*b^3 - 3*B*a^6*b^4 + A*a^5*b^5)*d*x)*tan(d*x + c)^4 + 2*(A*
a^9*b + B*a^8*b^2 - 2*B*a^6*b^4 + 6*B*a^4*b^6 - 11*A*a^3*b^7 + 3*B*a^2*b^8 - 6*A*a*b^9 + 2*(B*a^9*b - 3*A*a^8*
b^2 - 3*B*a^7*b^3 + A*a^6*b^4)*d*x)*tan(d*x + c)^3 + (A*a^10 + 4*B*a^9*b - 8*A*a^8*b^2 + 12*B*a^7*b^3 - 30*A*a
^6*b^4 + 23*B*a^5*b^5 - 45*A*a^4*b^6 + 9*B*a^3*b^7 - 18*A*a^2*b^8 + 2*(B*a^10 - 3*A*a^9*b - 3*B*a^8*b^2 + A*a^
7*b^3)*d*x)*tan(d*x + c)^2 + ((A*a^8*b^2 + 3*B*a^7*b^3 - 3*A*a^6*b^4 + 9*B*a^5*b^5 - 15*A*a^4*b^6 + 9*B*a^3*b^
7 - 17*A*a^2*b^8 + 3*B*a*b^9 - 6*A*b^10)*tan(d*x + c)^4 + 2*(A*a^9*b + 3*B*a^8*b^2 - 3*A*a^7*b^3 + 9*B*a^6*b^4
- 15*A*a^5*b^5 + 9*B*a^4*b^6 - 17*A*a^3*b^7 + 3*B*a^2*b^8 - 6*A*a*b^9)*tan(d*x + c)^3 + (A*a^10 + 3*B*a^9*b -
3*A*a^8*b^2 + 9*B*a^7*b^3 - 15*A*a^6*b^4 + 9*B*a^5*b^5 - 17*A*a^4*b^6 + 3*B*a^3*b^7 - 6*A*a^2*b^8)*tan(d*x +
c)^2)*log(tan(d*x + c)^2/(tan(d*x + c)^2 + 1)) - ((10*B*a^5*b^5 - 15*A*a^4*b^6 + 9*B*a^3*b^7 - 17*A*a^2*b^8 +
3*B*a*b^9 - 6*A*b^10)*tan(d*x + c)^4 + 2*(10*B*a^6*b^4 - 15*A*a^5*b^5 + 9*B*a^4*b^6 - 17*A*a^3*b^7 + 3*B*a^2*b
^8 - 6*A*a*b^9)*tan(d*x + c)^3 + (10*B*a^7*b^3 - 15*A*a^6*b^4 + 9*B*a^5*b^5 - 17*A*a^4*b^6 + 3*B*a^3*b^7 - 6*A
*a^2*b^8)*tan(d*x + c)^2)*log((b^2*tan(d*x + c)^2 + 2*a*b*tan(d*x + c) + a^2)/(tan(d*x + c)^2 + 1)) + 2*(B*a^1
0 - 2*A*a^9*b + 3*B*a^8*b^2 - 6*A*a^7*b^3 + 3*B*a^6*b^4 - 6*A*a^5*b^5 + B*a^4*b^6 - 2*A*a^3*b^7)*tan(d*x + c))
/((a^11*b^2 + 3*a^9*b^4 + 3*a^7*b^6 + a^5*b^8)*d*tan(d*x + c)^4 + 2*(a^12*b + 3*a^10*b^3 + 3*a^8*b^5 + a^6*b^7
)*d*tan(d*x + c)^3 + (a^13 + 3*a^11*b^2 + 3*a^9*b^4 + a^7*b^6)*d*tan(d*x + c)^2)

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giac [B]  time = 3.27, size = 812, normalized size = 2.31 \[ -\frac {\frac {4 \, {\left (B a^{3} - 3 \, A a^{2} b - 3 \, B a b^{2} + A b^{3}\right )} {\left (d x + c\right )}}{a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}} - \frac {2 \, {\left (A a^{3} + 3 \, B a^{2} b - 3 \, A a b^{2} - B b^{3}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}} - \frac {4 \, {\left (10 \, B a^{5} b^{4} - 15 \, A a^{4} b^{5} + 9 \, B a^{3} b^{6} - 17 \, A a^{2} b^{7} + 3 \, B a b^{8} - 6 \, A b^{9}\right )} \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{a^{11} b + 3 \, a^{9} b^{3} + 3 \, a^{7} b^{5} + a^{5} b^{7}} - \frac {3 \, A a^{7} b^{2} \tan \left (d x + c\right )^{4} + 9 \, B a^{6} b^{3} \tan \left (d x + c\right )^{4} - 9 \, A a^{5} b^{4} \tan \left (d x + c\right )^{4} - 3 \, B a^{4} b^{5} \tan \left (d x + c\right )^{4} + 6 \, A a^{8} b \tan \left (d x + c\right )^{3} + 14 \, B a^{7} b^{2} \tan \left (d x + c\right )^{3} - 6 \, A a^{6} b^{3} \tan \left (d x + c\right )^{3} - 34 \, B a^{5} b^{4} \tan \left (d x + c\right )^{3} + 56 \, A a^{4} b^{5} \tan \left (d x + c\right )^{3} - 36 \, B a^{3} b^{6} \tan \left (d x + c\right )^{3} + 68 \, A a^{2} b^{7} \tan \left (d x + c\right )^{3} - 12 \, B a b^{8} \tan \left (d x + c\right )^{3} + 24 \, A b^{9} \tan \left (d x + c\right )^{3} + 3 \, A a^{9} \tan \left (d x + c\right )^{2} + B a^{8} b \tan \left (d x + c\right )^{2} + 13 \, A a^{7} b^{2} \tan \left (d x + c\right )^{2} - 45 \, B a^{6} b^{3} \tan \left (d x + c\right )^{2} + 88 \, A a^{5} b^{4} \tan \left (d x + c\right )^{2} - 52 \, B a^{4} b^{5} \tan \left (d x + c\right )^{2} + 102 \, A a^{3} b^{6} \tan \left (d x + c\right )^{2} - 18 \, B a^{2} b^{7} \tan \left (d x + c\right )^{2} + 36 \, A a b^{8} \tan \left (d x + c\right )^{2} - 4 \, B a^{9} \tan \left (d x + c\right ) + 8 \, A a^{8} b \tan \left (d x + c\right ) - 12 \, B a^{7} b^{2} \tan \left (d x + c\right ) + 24 \, A a^{6} b^{3} \tan \left (d x + c\right ) - 12 \, B a^{5} b^{4} \tan \left (d x + c\right ) + 24 \, A a^{4} b^{5} \tan \left (d x + c\right ) - 4 \, B a^{3} b^{6} \tan \left (d x + c\right ) + 8 \, A a^{2} b^{7} \tan \left (d x + c\right ) - 2 \, A a^{9} - 6 \, A a^{7} b^{2} - 6 \, A a^{5} b^{4} - 2 \, A a^{3} b^{6}}{{\left (a^{10} + 3 \, a^{8} b^{2} + 3 \, a^{6} b^{4} + a^{4} b^{6}\right )} {\left (b \tan \left (d x + c\right )^{2} + a \tan \left (d x + c\right )\right )}^{2}} + \frac {4 \, {\left (A a^{2} + 3 \, B a b - 6 \, A b^{2}\right )} \log \left ({\left | \tan \left (d x + c\right ) \right |}\right )}{a^{5}}}{4 \, d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(d*x+c)^3*(A+B*tan(d*x+c))/(a+b*tan(d*x+c))^3,x, algorithm="giac")

[Out]

-1/4*(4*(B*a^3 - 3*A*a^2*b - 3*B*a*b^2 + A*b^3)*(d*x + c)/(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6) - 2*(A*a^3 + 3*B
*a^2*b - 3*A*a*b^2 - B*b^3)*log(tan(d*x + c)^2 + 1)/(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6) - 4*(10*B*a^5*b^4 - 15
*A*a^4*b^5 + 9*B*a^3*b^6 - 17*A*a^2*b^7 + 3*B*a*b^8 - 6*A*b^9)*log(abs(b*tan(d*x + c) + a))/(a^11*b + 3*a^9*b^
3 + 3*a^7*b^5 + a^5*b^7) - (3*A*a^7*b^2*tan(d*x + c)^4 + 9*B*a^6*b^3*tan(d*x + c)^4 - 9*A*a^5*b^4*tan(d*x + c)
^4 - 3*B*a^4*b^5*tan(d*x + c)^4 + 6*A*a^8*b*tan(d*x + c)^3 + 14*B*a^7*b^2*tan(d*x + c)^3 - 6*A*a^6*b^3*tan(d*x
+ c)^3 - 34*B*a^5*b^4*tan(d*x + c)^3 + 56*A*a^4*b^5*tan(d*x + c)^3 - 36*B*a^3*b^6*tan(d*x + c)^3 + 68*A*a^2*b
^7*tan(d*x + c)^3 - 12*B*a*b^8*tan(d*x + c)^3 + 24*A*b^9*tan(d*x + c)^3 + 3*A*a^9*tan(d*x + c)^2 + B*a^8*b*tan
(d*x + c)^2 + 13*A*a^7*b^2*tan(d*x + c)^2 - 45*B*a^6*b^3*tan(d*x + c)^2 + 88*A*a^5*b^4*tan(d*x + c)^2 - 52*B*a
^4*b^5*tan(d*x + c)^2 + 102*A*a^3*b^6*tan(d*x + c)^2 - 18*B*a^2*b^7*tan(d*x + c)^2 + 36*A*a*b^8*tan(d*x + c)^2
- 4*B*a^9*tan(d*x + c) + 8*A*a^8*b*tan(d*x + c) - 12*B*a^7*b^2*tan(d*x + c) + 24*A*a^6*b^3*tan(d*x + c) - 12*
B*a^5*b^4*tan(d*x + c) + 24*A*a^4*b^5*tan(d*x + c) - 4*B*a^3*b^6*tan(d*x + c) + 8*A*a^2*b^7*tan(d*x + c) - 2*A
*a^9 - 6*A*a^7*b^2 - 6*A*a^5*b^4 - 2*A*a^3*b^6)/((a^10 + 3*a^8*b^2 + 3*a^6*b^4 + a^4*b^6)*(b*tan(d*x + c)^2 +
a*tan(d*x + c))^2) + 4*(A*a^2 + 3*B*a*b - 6*A*b^2)*log(abs(tan(d*x + c)))/a^5)/d

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maple [B]  time = 0.76, size = 713, normalized size = 2.03 \[ \frac {6 \ln \left (\tan \left (d x +c \right )\right ) A \,b^{2}}{d \,a^{5}}-\frac {3 \ln \left (\tan \left (d x +c \right )\right ) B b}{d \,a^{4}}+\frac {3 A \arctan \left (\tan \left (d x +c \right )\right ) a^{2} b}{d \left (a^{2}+b^{2}\right )^{3}}+\frac {3 B \arctan \left (\tan \left (d x +c \right )\right ) a \,b^{2}}{d \left (a^{2}+b^{2}\right )^{3}}-\frac {A \arctan \left (\tan \left (d x +c \right )\right ) b^{3}}{d \left (a^{2}+b^{2}\right )^{3}}-\frac {B \arctan \left (\tan \left (d x +c \right )\right ) a^{3}}{d \left (a^{2}+b^{2}\right )^{3}}+\frac {3 A b}{d \,a^{4} \tan \left (d x +c \right )}+\frac {\ln \left (1+\tan ^{2}\left (d x +c \right )\right ) A \,a^{3}}{2 d \left (a^{2}+b^{2}\right )^{3}}-\frac {\ln \left (1+\tan ^{2}\left (d x +c \right )\right ) b^{3} B}{2 d \left (a^{2}+b^{2}\right )^{3}}+\frac {10 \ln \left (a +b \tan \left (d x +c \right )\right ) b^{3} B}{d \left (a^{2}+b^{2}\right )^{3}}+\frac {3 \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) a^{2} b B}{2 d \left (a^{2}+b^{2}\right )^{3}}-\frac {A \ln \left (\tan \left (d x +c \right )\right )}{a^{3} d}-\frac {A}{2 d \,a^{3} \tan \left (d x +c \right )^{2}}-\frac {B}{d \,a^{3} \tan \left (d x +c \right )}+\frac {5 b^{4} A}{d \,a^{2} \left (a^{2}+b^{2}\right )^{2} \left (a +b \tan \left (d x +c \right )\right )}-\frac {b^{3} B}{2 d \,a^{2} \left (a^{2}+b^{2}\right ) \left (a +b \tan \left (d x +c \right )\right )^{2}}+\frac {3 b^{6} A}{d \,a^{4} \left (a^{2}+b^{2}\right )^{2} \left (a +b \tan \left (d x +c \right )\right )}-\frac {4 b^{3} B}{d a \left (a^{2}+b^{2}\right )^{2} \left (a +b \tan \left (d x +c \right )\right )}-\frac {3 \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) A a \,b^{2}}{2 d \left (a^{2}+b^{2}\right )^{3}}+\frac {9 b^{5} \ln \left (a +b \tan \left (d x +c \right )\right ) B}{d \,a^{2} \left (a^{2}+b^{2}\right )^{3}}-\frac {6 b^{8} \ln \left (a +b \tan \left (d x +c \right )\right ) A}{d \,a^{5} \left (a^{2}+b^{2}\right )^{3}}-\frac {15 b^{4} \ln \left (a +b \tan \left (d x +c \right )\right ) A}{d a \left (a^{2}+b^{2}\right )^{3}}-\frac {17 b^{6} \ln \left (a +b \tan \left (d x +c \right )\right ) A}{d \,a^{3} \left (a^{2}+b^{2}\right )^{3}}-\frac {2 b^{5} B}{d \,a^{3} \left (a^{2}+b^{2}\right )^{2} \left (a +b \tan \left (d x +c \right )\right )}+\frac {b^{4} A}{2 d \,a^{3} \left (a^{2}+b^{2}\right ) \left (a +b \tan \left (d x +c \right )\right )^{2}}+\frac {3 b^{7} \ln \left (a +b \tan \left (d x +c \right )\right ) B}{d \,a^{4} \left (a^{2}+b^{2}\right )^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cot(d*x+c)^3*(A+B*tan(d*x+c))/(a+b*tan(d*x+c))^3,x)

[Out]

6/d/a^5*ln(tan(d*x+c))*A*b^2-3/d/a^4*ln(tan(d*x+c))*B*b+3/2/d/(a^2+b^2)^3*ln(1+tan(d*x+c)^2)*a^2*b*B+3/d/(a^2+
b^2)^3*A*arctan(tan(d*x+c))*a^2*b+3/d/(a^2+b^2)^3*B*arctan(tan(d*x+c))*a*b^2+1/2/d/(a^2+b^2)^3*ln(1+tan(d*x+c)
^2)*A*a^3-1/2/d/(a^2+b^2)^3*ln(1+tan(d*x+c)^2)*b^3*B-1/d/(a^2+b^2)^3*A*arctan(tan(d*x+c))*b^3-1/d/(a^2+b^2)^3*
B*arctan(tan(d*x+c))*a^3+3/d/a^4/tan(d*x+c)*A*b+10/d/(a^2+b^2)^3*ln(a+b*tan(d*x+c))*b^3*B-1/a^3/d*A*ln(tan(d*x
+c))-1/2/d*A/a^3/tan(d*x+c)^2-1/d/a^3/tan(d*x+c)*B+5/d*b^4/a^2/(a^2+b^2)^2/(a+b*tan(d*x+c))*A-3/2/d/(a^2+b^2)^
3*ln(1+tan(d*x+c)^2)*A*a*b^2-1/2/d*b^3/a^2/(a^2+b^2)/(a+b*tan(d*x+c))^2*B+3/d*b^6/a^4/(a^2+b^2)^2/(a+b*tan(d*x
+c))*A-4/d*b^3/a/(a^2+b^2)^2/(a+b*tan(d*x+c))*B+9/d*b^5/a^2/(a^2+b^2)^3*ln(a+b*tan(d*x+c))*B-6/d*b^8/a^5/(a^2+
b^2)^3*ln(a+b*tan(d*x+c))*A-15/d*b^4/a/(a^2+b^2)^3*ln(a+b*tan(d*x+c))*A-17/d*b^6/a^3/(a^2+b^2)^3*ln(a+b*tan(d*
x+c))*A-2/d*b^5/a^3/(a^2+b^2)^2/(a+b*tan(d*x+c))*B+1/2/d*b^4/a^3/(a^2+b^2)/(a+b*tan(d*x+c))^2*A+3/d*b^7/a^4/(a
^2+b^2)^3*ln(a+b*tan(d*x+c))*B

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maxima [A]  time = 0.84, size = 541, normalized size = 1.54 \[ -\frac {\frac {2 \, {\left (B a^{3} - 3 \, A a^{2} b - 3 \, B a b^{2} + A b^{3}\right )} {\left (d x + c\right )}}{a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}} - \frac {2 \, {\left (10 \, B a^{5} b^{3} - 15 \, A a^{4} b^{4} + 9 \, B a^{3} b^{5} - 17 \, A a^{2} b^{6} + 3 \, B a b^{7} - 6 \, A b^{8}\right )} \log \left (b \tan \left (d x + c\right ) + a\right )}{a^{11} + 3 \, a^{9} b^{2} + 3 \, a^{7} b^{4} + a^{5} b^{6}} - \frac {{\left (A a^{3} + 3 \, B a^{2} b - 3 \, A a b^{2} - B b^{3}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}} + \frac {A a^{7} + 2 \, A a^{5} b^{2} + A a^{3} b^{4} + 2 \, {\left (B a^{5} b^{2} - 3 \, A a^{4} b^{3} + 6 \, B a^{3} b^{4} - 11 \, A a^{2} b^{5} + 3 \, B a b^{6} - 6 \, A b^{7}\right )} \tan \left (d x + c\right )^{3} + {\left (4 \, B a^{6} b - 11 \, A a^{5} b^{2} + 17 \, B a^{4} b^{3} - 33 \, A a^{3} b^{4} + 9 \, B a^{2} b^{5} - 18 \, A a b^{6}\right )} \tan \left (d x + c\right )^{2} + 2 \, {\left (B a^{7} - 2 \, A a^{6} b + 2 \, B a^{5} b^{2} - 4 \, A a^{4} b^{3} + B a^{3} b^{4} - 2 \, A a^{2} b^{5}\right )} \tan \left (d x + c\right )}{{\left (a^{8} b^{2} + 2 \, a^{6} b^{4} + a^{4} b^{6}\right )} \tan \left (d x + c\right )^{4} + 2 \, {\left (a^{9} b + 2 \, a^{7} b^{3} + a^{5} b^{5}\right )} \tan \left (d x + c\right )^{3} + {\left (a^{10} + 2 \, a^{8} b^{2} + a^{6} b^{4}\right )} \tan \left (d x + c\right )^{2}} + \frac {2 \, {\left (A a^{2} + 3 \, B a b - 6 \, A b^{2}\right )} \log \left (\tan \left (d x + c\right )\right )}{a^{5}}}{2 \, d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(d*x+c)^3*(A+B*tan(d*x+c))/(a+b*tan(d*x+c))^3,x, algorithm="maxima")

[Out]

-1/2*(2*(B*a^3 - 3*A*a^2*b - 3*B*a*b^2 + A*b^3)*(d*x + c)/(a^6 + 3*a^4*b^2 + 3*a^2*b^4 + b^6) - 2*(10*B*a^5*b^
3 - 15*A*a^4*b^4 + 9*B*a^3*b^5 - 17*A*a^2*b^6 + 3*B*a*b^7 - 6*A*b^8)*log(b*tan(d*x + c) + a)/(a^11 + 3*a^9*b^2
+ 3*a^7*b^4 + a^5*b^6) - (A*a^3 + 3*B*a^2*b - 3*A*a*b^2 - B*b^3)*log(tan(d*x + c)^2 + 1)/(a^6 + 3*a^4*b^2 + 3
*a^2*b^4 + b^6) + (A*a^7 + 2*A*a^5*b^2 + A*a^3*b^4 + 2*(B*a^5*b^2 - 3*A*a^4*b^3 + 6*B*a^3*b^4 - 11*A*a^2*b^5 +
3*B*a*b^6 - 6*A*b^7)*tan(d*x + c)^3 + (4*B*a^6*b - 11*A*a^5*b^2 + 17*B*a^4*b^3 - 33*A*a^3*b^4 + 9*B*a^2*b^5 -
18*A*a*b^6)*tan(d*x + c)^2 + 2*(B*a^7 - 2*A*a^6*b + 2*B*a^5*b^2 - 4*A*a^4*b^3 + B*a^3*b^4 - 2*A*a^2*b^5)*tan(
d*x + c))/((a^8*b^2 + 2*a^6*b^4 + a^4*b^6)*tan(d*x + c)^4 + 2*(a^9*b + 2*a^7*b^3 + a^5*b^5)*tan(d*x + c)^3 + (
a^10 + 2*a^8*b^2 + a^6*b^4)*tan(d*x + c)^2) + 2*(A*a^2 + 3*B*a*b - 6*A*b^2)*log(tan(d*x + c))/a^5)/d

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mupad [B]  time = 12.87, size = 434, normalized size = 1.23 \[ \frac {\frac {\mathrm {tan}\left (c+d\,x\right )\,\left (2\,A\,b-B\,a\right )}{a^2}-\frac {A}{2\,a}+\frac {{\mathrm {tan}\left (c+d\,x\right )}^3\,\left (-B\,a^5\,b^2+3\,A\,a^4\,b^3-6\,B\,a^3\,b^4+11\,A\,a^2\,b^5-3\,B\,a\,b^6+6\,A\,b^7\right )}{a^4\,\left (a^4+2\,a^2\,b^2+b^4\right )}+\frac {{\mathrm {tan}\left (c+d\,x\right )}^2\,\left (-4\,B\,a^5\,b+11\,A\,a^4\,b^2-17\,B\,a^3\,b^3+33\,A\,a^2\,b^4-9\,B\,a\,b^5+18\,A\,b^6\right )}{2\,a^3\,\left (a^4+2\,a^2\,b^2+b^4\right )}}{d\,\left (a^2\,{\mathrm {tan}\left (c+d\,x\right )}^2+2\,a\,b\,{\mathrm {tan}\left (c+d\,x\right )}^3+b^2\,{\mathrm {tan}\left (c+d\,x\right )}^4\right )}+\frac {\ln \left (a+b\,\mathrm {tan}\left (c+d\,x\right )\right )\,\left (\frac {A}{a^3}-\frac {A\,a+3\,B\,b}{{\left (a^2+b^2\right )}^2}-\frac {6\,A\,b^2}{a^5}+\frac {3\,B\,b}{a^4}+\frac {4\,b^2\,\left (A\,a+B\,b\right )}{{\left (a^2+b^2\right )}^3}\right )}{d}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )-\mathrm {i}\right )\,\left (-B+A\,1{}\mathrm {i}\right )}{2\,d\,\left (-a^3\,1{}\mathrm {i}+3\,a^2\,b+a\,b^2\,3{}\mathrm {i}-b^3\right )}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )\right )\,\left (A\,a^2+3\,B\,a\,b-6\,A\,b^2\right )}{a^5\,d}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,\left (A-B\,1{}\mathrm {i}\right )}{2\,d\,\left (-a^3+a^2\,b\,3{}\mathrm {i}+3\,a\,b^2-b^3\,1{}\mathrm {i}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((cot(c + d*x)^3*(A + B*tan(c + d*x)))/(a + b*tan(c + d*x))^3,x)

[Out]

((tan(c + d*x)*(2*A*b - B*a))/a^2 - A/(2*a) + (tan(c + d*x)^3*(6*A*b^7 + 11*A*a^2*b^5 + 3*A*a^4*b^3 - 6*B*a^3*
b^4 - B*a^5*b^2 - 3*B*a*b^6))/(a^4*(a^4 + b^4 + 2*a^2*b^2)) + (tan(c + d*x)^2*(18*A*b^6 + 33*A*a^2*b^4 + 11*A*
a^4*b^2 - 17*B*a^3*b^3 - 9*B*a*b^5 - 4*B*a^5*b))/(2*a^3*(a^4 + b^4 + 2*a^2*b^2)))/(d*(a^2*tan(c + d*x)^2 + b^2
*tan(c + d*x)^4 + 2*a*b*tan(c + d*x)^3)) + (log(a + b*tan(c + d*x))*(A/a^3 - (A*a + 3*B*b)/(a^2 + b^2)^2 - (6*
A*b^2)/a^5 + (3*B*b)/a^4 + (4*b^2*(A*a + B*b))/(a^2 + b^2)^3))/d - (log(tan(c + d*x) - 1i)*(A*1i - B))/(2*d*(a
*b^2*3i + 3*a^2*b - a^3*1i - b^3)) - (log(tan(c + d*x))*(A*a^2 - 6*A*b^2 + 3*B*a*b))/(a^5*d) - (log(tan(c + d*
x) + 1i)*(A - B*1i))/(2*d*(3*a*b^2 + a^2*b*3i - a^3 - b^3*1i))

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sympy [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: AttributeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(d*x+c)**3*(A+B*tan(d*x+c))/(a+b*tan(d*x+c))**3,x)

[Out]

Exception raised: AttributeError

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